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random.shuffle(x[,random])

Shuffle the sequence x in place. The optional argument random is a 0-argument function returning a random float in [0.0,1.0); by default,this is the function random().

Note that for even rather small len(x),the total number of permutations of x is larger than the period of most random number generators; this implies that most permutations of a long sequence can never be generated.

如果我想重复获得[‘a’…’k’]的随机排列,似乎随机播放不会给我随机性.我的理解是对的吗？

谢谢！

解决方法

You don’t have anything to worry about.在len(x)下,2000年以下,random.shuffle应该可以正常工作.